DadofTwins wrote: ↑Mon Sep 10, 2018 11:40 pm
Double Jeopardy is the round that matters. But if I'm good enough to be a captain, I'm playing that myself. So my pick is going to be a FJ specialist. And of the players on the list, nobody is better at FJ than Ben Ingram.
I don't remember exactly where I heard this, but it may have been from one of the players involved so it could be legit. The info I got implied that each team is playing multiple games and each player will be limited on playing the same round, either not at all or not in consecutive games, so this changes things a bit.
With that in mind let's take another stab at the format. Let's say 8 games played in the first 8 of 10 days, and the Final is a two day affair. So each team plays 4 times, ensuring that they see every opponent either once or twice, and obviously the same set of 3 teams in a match should not be repeated. Rules for round assignemtns could either be:
a.) Each of the 3 players must play each of the 3 rounds at least once in the 4 matches.
or
b.) No player may play the same round in consecutive matches, though they do not have to play all 3 rounds over the 4.
Whichever of these rules is in place, I would start fresh with the 2 game final but say no one may play the same round in both halves.
How to determine the top 3 after 8 games? I thought that on Friday night the advance view of the website mentioned a wild card but now it does not. Much cleaner without it. Seems like two valid ways to go with this:
a.) The top 3 teams in total dollars accumulated advance to the finals, this seems unlikely as Jeopardy! is first about winning, not amassing dollars.
or
b.) Using some kind of a points system such as 5-3-1 or 3-2-1 for 1st-2nd-3rd in each match, top 3 teams by finish points earned advance to the finals, with total "dollars" available to be used as a tiebreaker.
Another wrinkle could be that the description clearly says head-to-head, is it possible that these games could be 2 teams only rather than 3? Seems much less like the Jeopardy! that we know but maybe it's a possibility. With one-on-one matches there could then be 9 games with each team playing 3 times, and then 3 in the single day final. In this format it would make sense to say all 3 players on each team must play each round once in the 3 qualifying games. The final 3 could still be decided by either method above, either W-L record or total dollars earned. Maybe even take the top 2 records and then call the 3rd a wild card for the remaining team with the most dollars earned.
